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Motor branch-circuit calculations (Article 430), step by step

Motor questions use three different percentages on two different currents, and most wrong answers come from mixing them up. The method is always the same: pick the right current, apply the right percentage, then round the way the NEC allows for that item. The examples below are for ordinary three-phase induction motors (Design B). The 2026 NEC adds Design BE and CE energy-efficient motors with their own rules, so read the motor design in the question.

Which current, which percentage

Table 430.250 is for three-phase motors. Use the column for the motor voltage, not the system voltage: a 460 V motor on a 480 V system uses the 460 V column.

What you sizeCurrent to usePercentageRoundingWhere to look (2026 NEC)
Branch-circuit conductors, one motorTable full-load current (FLC)125%Never round an ampacity down430.6(A)(1), Table 430.250, 430.22
Short-circuit and ground-fault protectionTable FLCInverse time breaker 250%, dual-element fuse 175%, nontime-delay fuse 300%Next higher standard size allowedTable 430.52(C)(1), 240.6(A)
Overload protectionNameplate current125% (service factor 1.15 or more, or 40 °C rise or less); 115% for other motorsNot more than the resultMotor overload rules in Article 430
Feeder conductors, several motorsTable FLC125% of the largest motor + 100% of the othersNever round an ampacity down430.24

Worked example 1: conductors use the table, not the nameplate

A 20 hp, 460 V, three-phase Design B motor has a nameplate current of 25 A. Table 430.250 gives 27 A.

Branch-circuit conductors: 27 × 1.25 = 33.75 A minimum ampacity.

Common wrong answer: 31.25 A (125% of the nameplate current).

Worked example 2: short-circuit and ground-fault protection

Same motor, table FLC 27 A. Maximum rating for each device type:

Inverse time breaker: 27 × 2.50 = 67.5 A. Not a standard size, so the next higher standard size, 70 A, is allowed.

Dual-element (time-delay) fuse: 27 × 1.75 = 47.25 A, so 50 A.

Nontime-delay fuse: 27 × 3.00 = 81 A. The next standard size above 80 A is 90 A.

Common wrong answers: 60 A (rounded the breaker down) and 33.75 A (used the conductor percentage).

Worked example 3: overload protection uses the nameplate

Same motor: nameplate 25 A, service factor 1.15. Maximum overload setting: 25 × 1.25 = 31.25 A.

If the motor had a service factor of 1.0 and a temperature rise above 40 °C, the limit would be 25 × 1.15 = 28.75 A.

Common wrong answer: 33.75 A (used the 27 A table current).

Worked example 4: feeder for three motors

A feeder supplies three 460 V, three-phase Design B motors: 30 hp (table FLC 40 A), 15 hp (21 A) and 10 hp (14 A). No other loads.

Minimum feeder ampacity: 40 × 1.25 + 21 + 14 = 85 A.

Common wrong answers: 93.75 A (125% applied to every motor) and 75 A (no 125% at all).

Worked example 5: one motor, three answers

A 50 hp, 460 V, three-phase Design B motor. Table FLC: 65 A.

Conductors: 65 × 1.25 = 81.25 A minimum ampacity.

Inverse time breaker: 65 × 2.50 = 162.5 A, so 175 A. Nontime-delay fuse: 65 × 3.00 = 195 A, so 200 A.

The three numbers are not related. A breaker larger than the conductor ampacity is normal for a motor circuit, because the overload device protects the conductors from overload.

Habits that save points

  • Circle "nameplate" and "table" in the question. Table FLC for conductors, short-circuit protection and feeders; nameplate only for overloads.
  • Check the motor voltage and phase before you read Table 430.250.
  • Round short-circuit protection up to the next standard size in 240.6(A). Never round an ampacity or an overload limit up.
  • In a feeder, apply 125% to the largest motor only.
  • Read the motor design. Design BE and CE motors have their own rules in the 2026 NEC, such as 430.22(H).

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Sources

Updated 2026-10-22. Found something wrong? Tell us and we will fix it and log the fix on our quality page.